#include <iostream>
#include <string>
#include <vector>
#include <algorithm>

using namespace std;

/**
 * Auto-generated code below aims at helping you parse
 * the standard input according to the problem statement.
 **/
int main()
{

	int n; // the number of temperatures to analyse
	cin >> n; cin.ignore();

	vector<int> temperatures;
	int current = 9999; // comparable value initialized with impossibly large value

	for (int i = 0; i < n; i++) {
		int t; // a temperature expressed as an integer ranging from -273 to 5526
		cin >> t; cin.ignore();
		temperatures.push_back(t); // push values to vector
	}

	if (!temperatures.empty()) // check, that actual data was given
	{
		for (auto itr : temperatures) // go though the vector
		{
			/* If the iterator is closer to 0 then current value
			** or if the iterated value is same, but positive
			** --> set current value to iterator.
			*/
			if (abs(itr) < abs(current) || current == -abs(itr))
				current = itr;
		}
	}
	else // if no data was given (n = 0)
	{
		current = 0;
	}
	// Write an action using cout. DON'T FORGET THE "<< endl"
	// To debug: cerr << "Debug messages..." << endl;

	cout << current << endl;
}


// Better solution: Thanks to CodinGames user Magaiti

/*
#include <iostream>
#include <iterator>
#include <algorithm>

using namespace std;

bool closer_to_zero (int i, int j) {
    return (abs(i) < abs(j)) || (abs(i) == abs(j) && i > 0);
}

int main() {
    istream_iterator<int> it(cin), eos;
    cout << (++it == eos ? 0 : *min_element (it, eos, closer_to_zero)) << endl;
}
*/