Electric Circuit of 5 Resistors

%% Electric Circuit of 5 Resistors
% Determines the equivalent resistance of the circuit
% Notes and Clarifications are at the end of the code

% Inputs and Variables
resis = input('Input resistances in brackets\n');

% Outputs and Equations
Rtot = resis(1) + resis(4) + (resis(3)*(resis(2)+resis(5)))/(resis(3)+(resis(2)+resis(5)));
fprintf('The total resistance is %.3e \n', Rtot);

if range(resis) == 0
    a = input('Would you like the calculate the current through R2 or R5? Y/N \n ', 's');
    if a == 'Y'
        V = input('What is the voltage of the circuit?\n');
        I = (V/Rtot)/resis(1);
        fprintf('The current running through R2/R5 is %.3e A \n', I)
    end
end
%{
The 'if' statement input requires a Y as a response to proceed with
    calculating the optional step.
Under the assumption that the resistors are in an 'x' formation while the
    numbering of the resistors is in a 'z' formation with R1 at the top left
    and R5 is at the bottom right.

If all the resistors have equal resistance, the amount of current that goes
    into R2 or R5 can be calculated. It can be calculated by finding the net
    current and dividing it by the resistance of an individual resistor.
    The code will run this optional path if requirements are met.

To solve this manually
    R2 and R5 are in series so they are added together  to equal R25
    R3 and R25 are is parallel so the inverse of the inverses added
        together equal R3,25
    R1, R4, and R3,25 are in series so they are added together
%}