N meetings in one room

'''
You want the meetings to end as quickly as possible so that you can allot the more meetings.
Always take the meeting with the earliest finishing time that doesn’t overlap.
'''
class Solution:

    #Function to find the maximum number of meetings that can
    #be performed in a meeting room.
    def maximumMeetings(self,start,end):
        arr=[]
        for i in range(len(start)):
            arr.append([end[i],start[i]]) #sort in increasing order as per the end time
        arr.sort()
        ans=0
        prev_finish=-1
        for i in arr:
            if i[1]>prev_finish: # if current meeting start time is afte the end time of the previous meeting, consider this meeting
                ans+=1
                prev_finish=i[0]
        return ans