skaiciavimas laiko

    for (int i = 0; i < n; i++)
    {
        val[i] = (m[i].pabV * 60 + m[i].pabM) - (m[i].pradV * 60 + m[i].pradM);
        min[i] = val[i] % 60;
        val[i] /= 60;
    }