Reverse a signed 32 bit int

/*
Given a 32-bit signed integer, reverse digits of an integer.

Example 1:

Input: 123
Output: 321
Example 2:

Input: -123
Output: -321
Example 3:

Input: 120
Output: 21
Note:
Assume we are dealing with an environment which could only store integers within the 32-bit signed integer range: [−231,  231 − 1]. For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows./*

*/
class Solution {
    public int reverse(int x) {
        int result = 0;
        while(x != 0){
            int lastDigit = x % 10;
            x /= 10;
            //check for overflow
            if(result>Integer.MAX_VALUE/10 || (result == Integer.MAX_VALUE/10 && lastDigit>7)){
             return 0;
            }
            if(result<Integer.MIN_VALUE/10 || (result == Integer.MIN_VALUE/10 && lastDigit <-8)){
                return 0;
            }
            result = result*10 + lastDigit;
        }
        return result;
    }
}