import itertools

# 可知y =1 ,而乘数后八位为range(2,10)的全排列。
# 至此，已经找出乘式中所有元素。

# first_pair为乘数每一位数 和其与easy相乘的首位数在全排列中的索引对儿元组
first_pair = [(0, 6), (1, 4), (2, 5), (4, 7), (5, 0), (6, 3), (7, 2)]

for i in itertools.permutations(range(2, 10)):
    easy = 1 + i[7] * 10 + i[3] * 100 + i[1] * 1000
    math_tuple = i[2:5] + i
    math_str = ''.join(map(str, math_tuple))
    maths = int(math_str)

    x = easy * maths

    if int(i[3] * easy / 10000) != 1:
        continue

    right = True
    for j in first_pair:
        if int(i[j[0]] * easy / 10000) != i[j[1]]:
            right = False
            continue

    if not right:
        continue

    if int(easy * maths / (10**14)) != i[5]:
        continue

    print(easy, " * ", maths)