Project to show distance between 2 place and Visiting places

#include<bits/stdc++.h>
using namespace std;
priority_queue<pair<int,int>,vector<pair<int,int>>>pq;
int main()
{
    int g,e,s,la,d,u;
    string f,l;
    string dha="Sonargaon, Lalbagh Kella, Ahsan Monjil.";
    string kum="Salbon Bihar, Dhormosagor, War Cemetery.";
    string khu="Sundarban, Satgombuj Mosque.";
    string shyl="Shahjalal Majar, Shahporan Majar, Jaflong.";
    string chi="Sitakundo, Cox's Bazar, Saint Martin.";
    vector<vector<pair<int,int>>>adlst(5+10);
    adlst[0].push_back(make_pair(1,150));
    adlst[0].push_back(make_pair(2,200));
    adlst[0].push_back(make_pair(3,120));
    adlst[1].push_back(make_pair(0,150));
    adlst[1].push_back(make_pair(3,100));
    adlst[2].push_back(make_pair(0,200));
    adlst[3].push_back(make_pair(0,120));
    adlst[3].push_back(make_pair(1,100));
    adlst[3].push_back(make_pair(4,185));
    adlst[4].push_back(make_pair(3,185));
    printf("First enter from where : ");
    cin>>f;
    printf("Now to which place : ");
    cin>>l;
    if(f=="Dhaka")s=0;
    else if(f=="Sylhet")s=1;
    else if(f=="Khulna")s=2;
    else if(f=="Kumilla")s=3;
    else if(f=="Chittagong")s=4;
    if(l=="Dhaka")la=0;
    else if(l=="Sylhet")la=1;
    else if(l=="Khulna")la=2;
    else if(l=="Kumilla")la=3;
    else if(l=="Chittagong")la=4;
    vector<int>dist(1e2+1,1e9);
    dist[s]=0;
    pq.push(pair<int,int>(0,s));
    while(!pq.empty()){
        pair<int,int>fron=pq.top();
        pq.pop();
        d=fron.first;
        u=fron.second;
        if(d>dist[u])continue;
        for(g=0;g<(int)adlst[u].size();g++){
            pair<int,int>v=adlst[u][g];
            if(dist[u]+v.second<dist[v.first]){
                dist[v.first]=dist[u]+v.second;
                pq.push(pair<int,int>(dist[v.first],v.first));
            }
        }
    }
    cout<<endl<<f<<" to "<<l;
    printf(": %d KM\n\n",dist[la]);
    printf("Visting Places : ");
    if(la==0)cout<<dha<<endl;
    else if(la==1)cout<<shyl<<endl;
    else if(la==2)cout<<khu<<endl;
    else if(la==3)cout<<kum<<endl;
    else if(la==4)cout<<chi<<endl;
    return 0;
}