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Alweys

2d polja zadatak d) - j)

Mar 24th, 2020 (edited)
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  1. #include <iostream>
  2. #include<stdlib.h>
  3.  
  4. using namespace std;
  5.  
  6. int main()
  7. {
  8. int a=rand()%21;
  9. int k=12;
  10. int s=12;
  11. int x[12][12];
  12. int min = x[0][0];
  13. int zbroj=0;
  14. for(int i=0;i<k;i++)
  15. {
  16. for(int j=0;j<s;j++)
  17. {
  18. x[i][j]=a;
  19.  
  20. if(x[i]==x[j])
  21. {
  22. x[i][j]=-1;
  23. cout<<x[i][j]<<" ";
  24. }
  25.  
  26. else if ((i+j)==(k-1))
  27. {
  28. x[i][j]=-2;
  29. cout<<x[i][j]<<" ";
  30. }
  31. else if((i+1)%2==0)
  32. {
  33. x[i][j]=-3;
  34. cout<<x[i][j]<<" ";
  35. }
  36. else if((i+1)%2!=0)
  37. {
  38. x[i][j]=-4;
  39. cout<<x[i][j]<<" ";
  40. }
  41. else
  42. cout<<x[i][j]<<" ";
  43. }
  44. cout<<endl;
  45. }
  46.  
  47. cout<<endl;
  48. for (int i = 0; i < k; i++)
  49. {
  50. for (int j = 0; j < s; j++)
  51. zbroj = zbroj + x[i][j];
  52. cout << "Zbroj " << i + 1 << ". retka je " << zbroj;
  53. zbroj = 0;
  54. cout << endl;
  55. }
  56. cout << endl;
  57. for (int i = 0; i < k; i++)
  58. {
  59. for (int j = 0; j < s; j++)
  60. if(min>x[i][j])
  61. min=x[i][j];
  62. cout << "Najmanji broj " << i + 1 << ". stupca je " << min;
  63. cout << endl;
  64. }
  65. return 0;
  66. }
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