ex3 lab2

function xc=iteratie(g,x0,k)
x(1)=x0;
for i=1:k
    x(i+1)=g(x(i));
end
xc=x(k+1);


% >>g=@(x) (1-x)^(1/5); -> avem x^5+x-1=0 de unde scoatem x=(1-x)^(1/5)
% >>xc=iteratie(g,0.8,10)