2225 . C. 樣本解析

#pragma GCC optimize("Ofast,no-stack-protector")
#include<bits/stdc++.h>
//#define int long long
#define quick ios::sync_with_stdio(0);cin.tie(0);
#define rep(x,a,b) for(int x=a;x<=b;x++)
#define repd(x,a,b) for(int x=a;x>=b;x--)
#define F first
#define S second
#define all(x) x.begin(),x.end()
#define mp make_pair
#define eb emplace_back
#define sz(x) (int)(x.size())
#define lowbit(x) (x&-x)
using namespace std;
typedef pair<int,int> pii;
typedef complex<int> P;
#define X real()
#define Y imag()
void debug(){
    cout<<"\n";
}
template<class T,class ...U>
void debug(T a,U ...b){
    cout<<a<<" ",debug(b...);
}
const int N=2e5+7;
const int INF=1e18;
bool p1(const string&v1,const string&v2){
    unordered_map<char,bool> m;
    for(char i:v1) m[i]=true;
    for(char i:v2){
        if(m.count(i)) return false;
    }
    return true;
}
bool p2(const string&v1,const string&v2){
    if(sz(v1)==sz(v2)) return false;
    unordered_map<char,bool> m;
    for(char i:v2) m[i]=true;
    for(char i:v1){
        if(!m.count(i)) return false;
    }
    return true;
}
bool p3(const string&v1,const string&v2){
    return p2(v2,v1);

}
bool eq(const string&v1,const string&v2){
    if(sz(v1)!=sz(v2)) return false;
    unordered_map<char,bool> m;
    for(char i:v2) m[i]=true;
    for(char i:v1){
        if(!m.count(i)) return false;
    }
    return true;
}
bool p4(const string&v1,const string&v2){
    return !p1(v1,v2)&&!p2(v1,v2)&&!p3(v1,v2)&&!eq(v1,v2);
}
string s[N];
int ans=0;
void dfs(const string&x,string x1,string x2,int st,int n,int l){
    rep(i,0,n-1){
        if(p4(x1,s[i])||p4(x2,s[i])) return ;
    }
    if(st>=l){
        ans++;
        return ;
    }
    dfs(x,string(x1+x[st]),x2,st+1,n,l);
    dfs(x,x1,string(x2+x[st]),st+1,n,l);
}

int cntp5(const string&x,int n){
    int l=sz(x);
    rep(i,0,n-1){
        rep(j,i+1,n-1){
            if(p4(s[i],s[j])){
                return 0;
            }
        }
    }
    ans=0;
    dfs(x,"","",0,n,l);
    return ans;
}

signed main(){
    quick

    int n;
    cin>>n;
    string x;
    cin>>x;
    rep(i,0,n-1){
        cin>>s[i];
    }
    int P1,P2,P3,P4;
    P1=P2=P3=P4=0;
    rep(i,0,n-1){
        P1+=p1(s[i],x);
        P2+=p2(x,s[i]);
        P3+=p3(x,s[i]);
        P4+=p4(s[i],x);
    }
    cout<<P1<<" "<<P2<<" "<<P3<<" "<<P4<<" "<<cntp5(x,n)<<"\n";

}