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Jan 21st, 2018
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C++
0.16 KB
| None
|
0
0
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print
report
char
str
[
100
]
;
for
(
i
=
0
;
str
[
i
]
==
"
\n
"
;
i
++
)
{
if
(
str
[
i
]
==
str
[
i
-
1
]
)
{
cout
<<
'одинаковые символы присутствуют'
;
break
;
}
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