import random
import struct
import sys

def bytes_to_long(s):
    """Convert a byte string to a long integer (big endian).

    In Python 3.2+, use the native method instead::

        >>> int.from_bytes(s, 'big')

    For instance::

        >>> int.from_bytes(b'\x00P', 'big')
        80

    This is (essentially) the inverse of :func:`long_to_bytes`.
    """
    acc = 0

    unpack = struct.unpack

    # Up to Python 2.7.4, struct.unpack can't work with bytearrays nor
    # memoryviews
    if sys.version_info[0:3] < (2, 7, 4):
        if isinstance(s, bytearray):
            s = bytes(s)
        elif isinstance(s, memoryview):
            s = s.tobytes()

    length = len(s)
    if length % 4:
        extra = (4 - length % 4)
        s = b'\x00' * extra + s
        length = length + extra
    for i in range(0, length, 4):
        acc = (acc << 32) + unpack('>I', s[i:i+4])[0]
    return acc
    e = 17

flag = "filler message go"
e = 17
n = 87248236976292375831726524431741785684972318062285568616700095704226943370108008367080490127391268247316969228948667432993586517883882862389422353850807246052106105023616135029870486239184167566566665353806935571175060912579679657097275204196999279619131945599336000635277556410739489817981698414802508845879

def prepare(message):
    return bytes_to_long(message.encode('utf-8'))

i = 0

def set_seed():
    i = random.randint(1, n)

set_seed()

for i in range(1, 5):
    new_flag = flag + str(i)
    print(prepare(new_flag))
    ct = pow(prepare(new_flag), e, n)
    print(f'{ct = }')
    set_seed()

print(f'{n = }')