yazdmich

PygLatin

Mar 22nd, 2013
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Python 0.42 KB | None | 0 0
  1. pyg = 'ay'
  2.  
  3. original = raw_input('Enter a word:')
  4.  
  5. if len(original) > 0 and original.isalpha():
  6.     print original
  7.     word = original.lower()
  8.     first = word[0]
  9.     if first == 'a' or first == 'e' or first == 'i' or first == 'o' or first == 'u':
  10.         new_word = word + pyg
  11.         print(new_word)
  12.     else:
  13.         new_word = word[1:len(word)] + word[0] + pyg
  14.         print(new_word)
  15. else:
  16.     print('empty')
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