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Oct 18th, 2017
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  1. procedure ins(var a:mas; n:integer);
  2. var i,j,v:integer;
  3. begin
  4. for i:=2 to n do begin
  5. v:=a[i]; j:=i-1;
  6. while (j>0) and (v<a[j]) do begin
  7. a[j+1]:=a[j];
  8. j:=j-1;
  9. end;
  10. a[j+1]:=v;
  11. end;
  12. end;
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