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- \documentclass[fleqn]{article}
- \usepackage[utf8]{inputenc}
- \usepackage[english,russian]{babel}
- \usepackage{indentfirst}
- \usepackage{misccorr}
- \usepackage{graphicx}
- \usepackage{amsmath}
- \usepackage[left=1in, right=1in, top=1in, bottom=1in]{geometry}
- \usepackage{mathexam}
- \usepackage{amsmath}
- \ExamClass{Котов Егор}
- \ExamName{Математическая статистика}
- \ExamHead{\today}
- \let\ds\displaystyle
- \begin{document}
- \begin{enumerate}
- \item $f(x) = e^{-a|x|}cos(bx)$
- \begin{enumerate}
- \item $\ds{\lim_{x\rightarrow3}\frac{\sqrt{x+1} - 2}{x-3}}$
- \item $\ds{\lim_{x\rightarrow0}\frac{\sin(4x)}{8x}}$
- \end{enumerate}
- \item Use the $\varepsilon$-$\delta$ definition of limit to prove that
- \[\lim_{x\rightarrow 2} x^2 - 3x + 2 = 0\]\noanswer[2.5in]
- \end{enumerate}
- \end{document}
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