(a) Write a shell script, called delimit, that removes from each line of a file the first occurrence of a text string
between an opening and closing delimiter. The specified delimiters are exactly one character, cannot be
the same character, and nested delimiters are ignored. Assume the following characters are not used as the
opening or closing delimiter: [ ] ^ $ .
*
/ \. The script must handle an arbitrarily long list of input files.
Print each input-file name on a separate line using the format “### filename ###” followed by the contents
of the entire file with lines modified as appropriate. The script has the following interface:
delimit opening-delimiter closing-delimiter input-file-list
For example, for input files:CS 246 - Assignment 1 3
$ cat input1.txt
(abc)
aa (a(d)xe)) (b) (c)fff
asdf(aakk
e)zz (ala)oe
$ cat input2.txt
abc(123
the output from the command is:
$ delimit
′
)
′
′
(
′
input1.txt input2.txt
### input1.txt ###
aa xe)) (b) (c)fff
asdf(aakk
e)zz oe
### input2.txt ###
abc(123
Hint, use the sed command to find and edit the lines of a file.
Modify the delimit script to have a -i option that means generate the inverse output without the delimiters;
i.e., it only prints the text-string and no delimiters. For example, the output from the command is:
$ delimit -i
′
)
′
′
(
′
input1.txt input2.txt
### input1.txt ###
abc
a(d
ala
### input2.txt ###
Hint, sed has a mechanism to store and use parts of a matched pattern.
Solve and test the first part of the question, and then add and test the second part of the question. Only
hand in a single script containing the solution to both parts; but if you cannot complete the second part,
still hand in the solution to the first part.