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Horikita_Suzune

Untitled

Jul 3rd, 2019
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C++ 0.11 KB | None | 0 0
  1. long long sumxor(long long N){
  2. int ans=0;
  3. for(long long i=0;i<N;i++){if((N^i)==(N+i))ans++}
  4. return ans;
  5. }
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