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- clear all, close all, clc
- N=10; Li=2.0; Ls=4.0; h=(Ls-Li)/N;
- x=Li:h:Ls; y=(log10(x)+x.^2)./(x+3).^2; I=0; z=0;
- disp('DIVISAO DE SUBINTERVALOS')
- for i=1:N/2
- A=[i+z,i+1+z,i+2+z]; disp(num2str(A));
- I=I+(h/3)*(y(i+z)+4*y(i+1+z)+y(i+2+z));
- z=z+1;
- end
- disp(' '); disp(['A integral vale:' num2str(I)]);
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