/*-Program opens with a dialog box requesting two integers.
  -Box can be given either two integers or 'stop'
  -If the string given is not stop, the StringTokenizer program
    will break down the string into individual strings.
  -These strings can then be converted to integers.
  -If given two integers, the first determines which math
   problem to use and the second is the value of n
  -The math problem requires a loop to sum the answers from 1 to n.
    (In both directions for problem 23 and just forward for problem 25)
  -A results window will display showing two answers for problem 23, one from
   the begining and one from the end.
  -A results window will display the approximation of Pi for problem 25
  -Clicking okay will restart the program
  -If given 'stop' the program will terminate
*/

import java.util.StringTokenizer;
import javax.swing.JOptionPane;
import java.text.DecimalFormat;

public class n00810678 {
    public static void main(String[] args) {

    //Variables
    double RL     = 0.0;
    double LR     = 0.0;
    double a      = 0.0;
    double b      = 0.0;
    double c      = 0.0;
    double result = 0.0;
    String gn     = "go";
    int bn         = 0;

    //Input Dialog Box

    do {

            String sn = JOptionPane.showInputDialog("Enter Problem number and n value");

            gn = sn;

            if (sn.equals("stop"))
            System.exit(0);
            else;

    //String Tokenizer

            StringTokenizer tn = new StringTokenizer(sn, "= ");

            while (tn.hasMoreTokens())
            {
                String STproblem = st.nextToken();
                String STnValue  = st.nextToken();

            //{System.out.println(tn.nextToken());}

    //Convert string to int

        int problem = Integer.parseInt(STproblem);
        int nValue  = Integer.parseInt(STnValue);

            //int n = bn;

            //n = Integer.parseInt(tn);
            System.out.println( nValue + problem);

//Problem 23________________________________________________________


    //Forward Loop

    for(int i = 1; i <= n; i++)

        {a = 1 / (float)i;
        RL = (RL + a);}

    //Reverse Loop

    for (int j = n; j >= 1; j--)

        {b = 1 / (float)j;
        LR = (LR + b);}

    //Output Dialog box for 23

    DecimalFormat dec = new DecimalFormat("###.##");

    String output = ("Sum of the series from left to right: " + dec.format(LR) +
                       "\nSum of the series from right to left: " + dec.format(RL));

    JOptionPane.showMessageDialog(null, output);

    } while (!gn.equals("stop"));
/*
//Problem 25_________________________________________________________________________

    String sn = JOptionPane.showInputDialog("Enter Problem number and n");

        double n = Double.parseDouble(sn);

        for(int i = 0; i <= n; i++)

        {c = (4.0 * (Math.pow((-1.0),i) * (1.0 / (2.0 * i + 1.0))));
         result = (result + c);
         System.out.println(c);}

    //Dialog Ouput box for Problem 25

    String output = ("Sum of the series: " + result);

    JOptionPane.showMessageDialog(null, output);
 */

}
}