int get_sum(string s) {
  vector<int> v;
  regex p("\\d+");
  smatch m;

  while (regex_search(s, m, p)) {
    if(m.size()) v.push_back(stoi(static_cast<string>(m[0])));
    s = m.suffix();
  }

  return accumulate(v.begin(), v.end(), 0, [](const int& a, const int& b) -> int {
    return b & 1 ? a + (int)pow(double(b), 2.0) : a;
  });
}