do1;
do2;
do3;
if result1>result2
    min = result2;
    max = result1;
else
    max = result2;
    min = result1;
end

min = 0.8*min;
max = 1.2*min;
if result3>min && result3<max
    'ta sama osoba'
else
    'nie ta sama osoba'
end