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Dec 15th, 2017
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  1. void F6(char c[], int nn)
  2. {
  3. int k, mm;
  4. for (mm = nn, k = 0; mm != 0; mm /= 10, k++);
  5. for (c[k--] = '\0'; k >= 0; k--)
  6. {
  7. c[k] = nn % 10 + '0'; nn /= 10;
  8. }
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