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Feb 20th, 2018
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text 0.22 KB | None | 0 0
  1. SELECT date, count(user) as count FROM sessions GROUP BY date;
  2.  
  3. 2018-02-01 | 0
  4. 2018-02-02 | 0
  5. 2018-02-03 | 0
  6. 2018-02-04 | 0
  7. 2018-02-05 | 1503582
  8. 2018-02-06 | 0
  9. 2018-02-06 | 0
  10. 2018-02-08 | 5612270
  11. ...
  12. ...
  13. ...
  14. 2018-02-31 | 0
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