Task 10 py

from operator import itemgetter
from pprint import pprint


def f(lst):
    n = []
    for i in lst:
        if i not in n and not None:
            n.append(i)
    return n


def qq(seq):
    seq = list(dict.fromkeys(seq))
    # print(seq)
    seq.remove(None)
    return seq


def streep(s):
    s = list(s)
    s.insert(3, "-")
    s = ''.join(s)
    return s


def main(data: list):
    data = f(data)
    seen = set()
    seen.add(None)
    seen.add("N")
    newdata = []
    for item in data:
        newdata.append(qq(item))
    data = newdata
    for i in range(len(data)):
        data[i][0] = data[i][0].split("/")
        data[i][0] = str(data[i][0][2] + "-" +
                         data[i][0][1] + "-" + data[i][0][0])
        data[i][1] = data[i][1].split("[at]")[0]
        if data[i][2] == 'N':
            data[i][2] = '0'
        else:
            data[i][2] = '1'
        data[i][3] = streep(data[i][3])
    if data[0][1] == 'bumidi8':
        data = sorted(data, key=itemgetter(2))
    else:
        data = sorted(data, key=itemgetter(1))
    one = []
    two = []
    three = []
    four = []
    newdata = []
    for item in data:
        one.append(item[0])
        two.append(item[1])
        three.append(item[2])
        four.append(item[3])
    newdata.append(one)
    newdata.append(two)
    newdata.append(three)
    newdata.append(four)
    return newdata

data = [
    ['09/11/00', None, 'rubberg31[at]mail.ru', 'rubberg31[at]mail.ru', None, 'N', '7576626'],
    ['08/01/01', None, 'buzobuk97[at]gmail.com', 'buzobuk97[at]gmail.com', None, 'N', '1334773'],
    ['08/01/01', None, 'buzobuk97[at]gmail.com', 'buzobuk97[at]gmail.com', None, 'N', '1334773'],
    ['07/11/01', None, 'kekak14[at]yandex.ru', 'kekak14[at]yandex.ru', None, 'Y', '3414751'],
    ['08/01/01', None, 'buzobuk97[at]gmail.com', 'buzobuk97[at]gmail.com', None, 'N', '1334773'],
    ['08/09/99', None, 'ducic47[at]yandex.ru', 'ducic47[at]yandex.ru', None, 'Y', '4486173']
]
main(data)