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- Proposicion:
- (P & Q)->¬R:R->(P->¬Q)
- Modus tollens
- -(-R) -> -(p&Q)
- Aplicando doble negacion
- R -> -(p&Q)
- p => -q
- 0 1 1
- 0 1 0
- 1 1 1
- 1 0 0
- p p/\q q
- 0 0 0
- 0 0 1
- 1 0 0
- 1 1 1
- p -(p/\q) q
- 0 1 0
- 0 1 1
- 1 1 0
- 1 0 1
- Las tablas de verdad de -(p&q) y (p=>q) son identicas, luego son operaciones equivalentes, lqqd.
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