PHP debug to console

<?php
/**
 * Send debug code to the Javascript console
 */
function debug_to_console($data) {
    if(is_array($data) || is_object($data))
    {
        echo("<script>console.log('PHP: ".json_encode($data)."');</script>");
    } else {
        echo("<script>console.log('PHP: ".$data."');</script>");
    }
}
?>