shoyebzz

Jagascript GET URL Parameter

Apr 15th, 2015 (edited)
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  1. <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js"></script>
  2.  
  3. <span id="devappp"></span>
  4. <script>
  5. function getUrlParameter(sParam)
  6. {
  7.     var sPageURL = window.location.search.substring(1);
  8.     var sURLVariables = sPageURL.split('&');
  9.     for (var i = 0; i < sURLVariables.length; i++)
  10.     {
  11.         var sParameterName = sURLVariables[i].split('=');
  12.         if (sParameterName[0] == sParam)
  13.         {
  14.             return sParameterName[1];
  15.         }
  16.     }
  17. }  
  18.  
  19. var devGet = getUrlParameter('dev');
  20.  
  21. if(devGet == 'mrz'){
  22.     jQuery('#appp').append(' | Developed by <a href="https://mashiurz.com"><b>Mashiurz</b></a>');
  23. }
  24. </script>
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