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- create table funcionario (
- cpf int,
- nome varchar(62),
- data_nasc date,
- salario float
- );
- in sert into funcionarios values
- (734, gabriela, 10091996, 7000);
- update funcionarios set salario = 700 where cpf 5435435.
- algebra relacional.
- operador SELECT
- WERE= CONDICAO
- SELECT * FROM FUNCIONARIO WHERE SALARIO = 5000
- SE QUISER OS NOMES DO QUE SAO ACIMA DE: SELECT FROM NOMES WHERE SALARIO > 5000
- W3Schools, SQL - https//www.w3schools.com/sql/
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