_takumi

number_of_divisors

Apr 22nd, 2021
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C++ 0.18 KB | None | 0 0
  1. int F(int n) {
  2.     set<int> ans;
  3.     for (int i = 2; i <= n; i++) {
  4.         if (n % i == 0) {
  5.             ans.insert(i);
  6.             while (n % i == 0)
  7.                 n /= i;
  8.             i = 2;
  9.         }
  10.     }
  11.     return ans.size();
  12. }
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