a = [3, 3, 2]
b = [6, 5, 2]

def is_cross(a, b):
    x1 = a[0]
    y1 = a[1]
    r1 = a[2]

    x2 = b[0]
    y2 = b[1]
    r2 = b[2]

    distance = (max(x1, x2) - min(x1, x2))**2 + max(y1, y2) - min(y1, y2)**2 # расстояние между точками в квадрате

    if ( (x1 + r1) >= (x2 - r2) and (x1 - r1) <= (x2 + r2) ) and ( (y1 + r1) >= (y2 - r2) and (y1 - r1) <= (y2 + r2) ) and ((r1 + r2)**2 >= distance):
        return True
    else:
        return False

print(is_cross(a,b))