sashomaga

SQL queries

Jul 30th, 2013
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SQL 1.74 KB | None | 0 0
  1. SELECT  e.FirstName + ' ' + e.LastName AS [FULL Name], e.Salary FROM  Employees AS e
  2.  
  3. SELECT  FirstName + '.' + LastName +'@telerik.com' AS [Email Address] FROM  Employees
  4.  
  5. SELECT  DISTINCT salary FROM Employees
  6.  
  7. SELECT * FROM Employees WHERE JobTitle = 'Sales Representative'
  8.  
  9. SELECT FirstName, LastName FROM Employees WHERE FirstName LIKE 'sa%'
  10.  
  11. SELECT FirstName, LastName FROM Employees WHERE LastName LIKE '%ei%'
  12.  
  13. SELECT FirstName, LastName FROM Employees WHERE Salary BETWEEN 20000 AND 30000
  14.  
  15. SELECT FirstName, LastName FROM Employees WHERE Salary IN (25000, 14000, 12500 ,23600)
  16.  
  17. SELECT FirstName, LastName FROM Employees WHERE ManagerID IS NULL --=(equal) don't work for null
  18.  
  19. SELECT FirstName, LastName, Salary FROM Employees WHERE Salary > 50000 ORDER BY Salary DESC
  20.  
  21. SELECT TOP 5 FirstName, LastName, Salary FROM Employees ORDER BY Salary DESC
  22.  
  23. SELECT e.FirstName +' '+ e.LastName AS [FULL Name], a.AddressText FROM Employees e JOIN Addresses a ON e.AddressID = a.AddressID
  24.  
  25. --equi join
  26. SELECT e.FirstName +' '+ e.LastName AS [FULL Name], a.AddressText FROM Employees e ,Addresses a WHERE e.AddressID = a.AddressID
  27.  
  28. --self join
  29. SELECT e.FirstName AS Employee, m.FirstName AS Manager FROM Employees e LEFT OUTER JOIN Employees m ON e.ManagerID = m.EmployeeID
  30.  
  31. --3 tables join
  32. SELECT e.FirstName AS Employee, a.AddressText AS Address, m.FirstName AS Manager FROM Employees e LEFT OUTER JOIN Employees m ON e.ManagerID = m.EmployeeID JOIN Addresses a ON
  33. e.AddressID = a.AddressID
  34.  
  35. SELECT d.Name FROM Departments d
  36. UNION
  37. SELECT t.Name FROM Towns t
  38.  
  39. SELECT e.FirstName FROM Employees e JOIN Departments d ON e.DepartmentID = d.DepartmentID WHERE d.Name IN ('Sales', 'Finance') AND (e.HireDate  BETWEEN '1995-01-01' AND '2005-01-01')
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