#include <bits/stdc++.h>
using namespace std;

#define FOR(i,a,b) for (int i = (a); i < (b); i++)
#define RFOR(i,b,a) for (int i = (b) - 1; i >= (a); i--)
#define ITER(it,a) for (__typeof(a.begin()) it = a.begin(); it != a.end(); it++)
#define FILL(a,value) memset(a, value, sizeof(a))

#define SZ(a) (int)a.size()
#define ALL(a) a.begin(), a.end()
#define PB push_back
#define MP make_pair

typedef long long LL;
typedef vector<int> VI;
typedef pair<int, int> PII;

const double PI = acos(-1.0);
const int INF = 1000 * 1000 * 1000 + 7;
const LL LINF = INF * (LL) INF;

const int MAX = 30300;

const double EPS = 1e-7;

struct Point
{
    double x, y;
    Point(double x, double y)
    {
        this->x = x;
        this->y = y;
    }
    Point(){}
} A[MAX];

int main()
{
    //freopen("in.txt", "r", stdin);
    //ios::sync_with_stdio(false); cin.tie(0);

    int n;
    while(scanf("%d", &n) != EOF)
    {
        double a;
        scanf("%lf", &a);
        FOR (i, 0, n)
        {
            scanf("%lf", &A[i].x);
        }

        FOR (i, 0, n)
        {
            scanf("%lf", &A[i].y);
        }

        int cnt = 0;
        vector<pair<double, int> > E;

        FOR (i, 0, n)
        {
            if (abs(A[i].x) < 0 && abs(A[i].y) < 0)
            {
                cnt++;
                continue;
            }
            double r2 = A[i].x * A[i].x + A[i].y * A[i].y;
            double d = 1 + 4 * a * a * r2;
            double x = (sqrt(d)  - 1) / (2*a);

            double y = sqrt(r2 - x*x);

            double a1 = atan2(A[i].y, A[i].x);
            double a2 = atan2(y, x);

            double ang1 = a1 - a2;
            double ang2 = a1 + a2;

            while(ang1 < EPS) ang1 += 2 * PI;
            while(ang1 > 2*PI - EPS) ang1 -= 2*PI;

            while(ang2 < EPS) ang2 += 2 * PI;
            while(ang2 > 2*PI - EPS) ang2 -= 2*PI;

            E.PB(MP(ang1 - EPS, 1));
            E.PB(MP(ang2 + EPS, -1));

            if (ang1 > ang2) cnt++;
        }

        sort(ALL(E));
        int res = cnt;

        FOR (i, 0, SZ(E))
        {
            cnt += E[i].second;
            res = max(res, cnt);
        }

        printf("%d daze\n", res);
    }
}