Advertisement
Guest User

Untitled

a guest
Oct 22nd, 2019
76
0
Never
Not a member of Pastebin yet? Sign Up, it unlocks many cool features!
text 0.84 KB | None | 0 0
  1. print('''
  2. ######################################################
  3. ######################################################
  4. ######THIS SCRIPT IS WRITTEN BY CH4N(Team_Hydra)######
  5. ######################################################
  6. ######################################################''')
  7. import re
  8. text = "313235343034313231343034373634303431303834303439373430343738343034313035343034373034303439353430343834343034313035343034393534303436383430343130353430343130303430343935343034313137343034343834303438393430343935343034313031343034313039343034343834303438333430343531343034313139343034363534303431323334303435373430343439343034343834303435303430343637343034383334303436373430343737343034"
  9. num = text.decode("hex")
  10. n = ""
  11. number = "404"
  12. x = re.sub(number,n,num)
  13. flag = re.sub('1?..', lambda m: chr(int(m.group())), x)
  14.  
  15. print "FLAG =" ,flag[::-1]
Advertisement
Add Comment
Please, Sign In to add comment
Advertisement