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  1. #include <iostream>
  2. #include <fstream>
  3. using namespace std;
  4. ifstream f("tema.in");
  5.     ofstream g("tema.out");
  6. void Simplificare(long long a,long long b)
  7. {
  8.     long long r,auxa,auxb;
  9.     auxa=a;
  10.     auxb=b;
  11.     r=1;
  12.     while(r!=0)
  13.     {
  14.         r=auxa%auxb;
  15.         auxa=auxb;
  16.         auxb=r;
  17.  
  18.     }
  19.     g<<a/auxa<<" "<<b/auxa<<endl;
  20.  
  21. }
  22.  
  23.  
  24.  
  25.  
  26.  
  27.  
  28. int main()
  29. {
  30.  long long n,i,p1,p2,p3,aux2,c = 1,nur,num,aux1,aux3,m,s;
  31. f>>n;
  32. for(i=0;i<n;i++)
  33. {
  34.     f>>p1>>p2>>p3;
  35.     aux1=p1;
  36.     aux2=p2;
  37.     aux3=p3;
  38.  
  39.     if(p2 != -1 && p3 == -1)
  40.     {
  41.         c=1;
  42.         while(aux2>0)
  43.     {
  44.         aux2=aux2/10;
  45.         c=c*10;
  46.     }
  47.     nur=p1*c+p2;
  48.  
  49.     Simplificare(nur,c);
  50.     }
  51.     if(p2 == -1 && p3 != -1)
  52.     {   c=10;
  53.         num=9;
  54.  
  55.         while(aux3>10)
  56.         {
  57.             aux3=aux3/10;
  58.             c=c*10;
  59.             num=num*10+9;
  60.         }
  61.  
  62.         nur=p1*c+p3-p1;
  63.  
  64.         Simplificare(nur,num);
  65.     }
  66.     if(p2 != -1 && p3 != -1)
  67.     {   m=10;
  68.         s=1;
  69.         c=10;
  70.         num=9;
  71.         while(aux3>10)
  72.         {
  73.             aux3=aux3/10;
  74.             c=c*10;
  75.             m=m*10;
  76.             num=num*10+9;
  77.  
  78.         }
  79.         while(aux2>1)
  80.         {
  81.             aux2=aux2/10;
  82.             c=c*10;
  83.             s=s*10;
  84.             num=num*10;
  85.         }
  86.  
  87.         nur=p1*c+m*p2+p3-p1*s-p2;
  88.  
  89.         Simplificare(nur,num);
  90.     }
  91. }
  92.     return 0;
  93.  
  94.  
  95. }
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