speedoflightspheres

NB. Point is that the final values should be around 144.000 or 144.000.0 whatever which is for the maximum speed of light in geodesic miles..The problem is that many times multiplying with six will either show eventually this ~144 or 1/144 but I can't find the pattern or so what other things these values could be multiplied to give a system to end up with these geodesic values. I've tried with luck and found a handful yet of a handful that fit in relation to a few extra that didn't fit but I'm betting there is something with this.

pentsum(x-2/2) *6**n show some entries to give speed-of-light harmonics. is there a pattern? if so what is it. The geodesic miles (maximum) speed of light in vaccum is 144.000 (nautical miles x 1.125) in this context could be a decimal harmonic 14400 etc.


I found the answer before you could reply I guess it's some gravity harmonics related to spheres but not gravity-attraction probably, this makes it harder to solve I guess though you could still try to solve the math-riddle if you want to.

Thank you!
Chris.
På mandag 2. desember 2019, 16:48:07 CET skrev Krister Z-F. Lilleland <chris_zfl7@yahoo.com> følgende:


Rod.

I have something I was wondering if you could verify as a mathematician. It would help if you could look at it as math is not so natural for me which makes it at least too tedious too do. I

With my software and some algorithms I found that Buckminster's closest packed spheres could be , it could be calculated between the two what the gravity would be possibly I wrote Amy Edmondson (his student) about it but I got no reply. I think it is at least vaguely interesting for and also vaguely possible that it provides an alternate way of calculating gravity.

I don't know if you know Python programming / scripting which I used but this is so simple any programmer should do understand it.

A typical output of the program I made is like this:

>>> gravity(130,488) #use the pentsum function on the two values no pentsum(x-2/y)

11.05625

>>> _*6

66.3375

>>> _*6

398.02500000000003

>>> _*6

2388.15

>>> _*6

14328.900000000001

>>> 1/_

6.978902776905414e-05

>>> 14328.900000000001-14400

-71.09999999999854

>>>

What it does is convert the input x and y to a suitable format with these:

def pentsum(n):return(pentacle(n)+repentacle(n)) # this one combines the two below and is the one used for output
def pentacle(n):return 1/(n*5/2)
def repentacle(n):return 1/(n*2/5)

additionally with this x-2 for first sphere and without -2 for the second, I tried it without -2 and got no result the -2 is for the axis.:



return(pentsum((x-2)/y)) # this converts the values from sphere equations below , values divided by each other as you see I think one think I don't know about is which one to come first in the calculation.

x and y in the above is calculated from the number of spheres only in the outer layer of a "closest packed nesting" system of spheres. With Buckminster Formula 2nf²+2 where n is form of the closest packing primes 1,2,3,5 for Tetrahardon / Octahardon and so on. And n is the frequency i.e. layer.

Thank you!
Chris.

Two more examples:

>>> harmonic(1446,1602) (computer function)
3.217313019390582
(real gravity "potential"?) >>> _*6
19.30387811634349
>>> _*6
115.82326869806094 >>> _*6
694.9396121883657 (gravity-meters/sec?)
>>> 1/_
0.0014389739517812186 (speed-of-light reciprocal)

>>> harmonic(1962,362)
0.5356122448979592
>>> _*6
3.2136734693877553
>>> _*6
19.282040816326532
>>> _*6
115.6922448979592
>>> _*6
694.153469387755