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MatsGranvik

Square root of Möbius function asymptotic

Aug 10th, 2018
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  1. (*Square root of Möbius function asymptotic*)
  2. nn = 1000;
  3. s = N[1/2 + 1/100];
  4. Show[ListLinePlot[
  5. Re[Accumulate[Table[(MoebiusMu[n])^(1/2)/n^(s), {n, 1, nn}]]]],
  6. ListLinePlot[
  7. Table[Re[3/Pi^2*(Zeta[s] - k^(1 - s)/(s - 1) + (k^(-s))/2 + s)], {k,
  8. 1, nn}], PlotStyle -> Red]]
  9.  
  10. s = 1/2 + 1/1000;
  11. Show[ListLinePlot[
  12. Table[Sum[1/n^s, {n, 1, k}]*(3/Pi^2), {k, 1, 40, 1/10}]],
  13. ListLinePlot[
  14. Table[(Zeta[s] - k^(1 - s)/(s - 1))*(3/Pi^2), {k, 1, 40, 1/10}],
  15. PlotStyle -> Red]]
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