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- # solve for Z - >[L][Z]=[C]
- Z(1) = b(1);
- for i = 2 : n
- sum = 0;
- for j = i - 1:-1:1
- sum = sum + (L(i,j) * Z(j));
- endfor
- Z(i) = b(i) - sum;
- endfor
- ##disp(Z);
- # solve for X -> [U][X]=[Z]
- X(n) = Z(n) / U(n,n);
- for i = n - 1: -1: 1
- sum = 0;
- for j = i + 1:1:n
- sum = sum + (U(i,j)*X(j));
- endfor
- X(i) = (Z(i) - sum) / U(i,i);
- endfor
- disp(X);
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