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  1. #include<bits/stdc++.h>
  2. #define ff first
  3. #define ss second
  4. #define pii pair<int, int>
  5. #define int long long
  6. #define pb push_back
  7. #define eb emplace_back
  8. #define all(x) (x).begin(), (x).end()
  9.  
  10. using namespace std;
  11. const int maxn = 3e5 + 7, inf = 1e18;
  12. int n;
  13. int cnt[maxn];
  14.  
  15. struct fenwik {
  16. int t[maxn];
  17. int k[maxn];
  18. vector<int> update;
  19. int get(int r) {
  20. int cur = 0;
  21. for (int i = r; i >= 0; i |= i + 1) {
  22. cur += t[i];
  23. }
  24. return cur;
  25. }
  26. int sum(int l, int r) {
  27. if (l == 0) return get(r);
  28. return get(r) - get(l - 1);
  29. }
  30. void upd(int id, int x) {
  31. if (k[id] == x) {
  32. return;
  33. }
  34. k[id] = x;
  35. for (int i = id; i >= 0; i &= i + 1, --i) {
  36. t[i] += x;
  37. update.pb(i);
  38. }
  39. }
  40. void clear() {
  41. for (auto v : update) {
  42. t[v] = 0;
  43. k[v] = 0;
  44. }
  45. }
  46.  
  47. };
  48.  
  49. int len = 1;
  50. vector<int> tree;
  51.  
  52. void build(int sz) {
  53. while (len < sz) len <<= 1;
  54. tree.resize(len + len - 1);
  55. }
  56.  
  57. int getl(int l, int r, int l1, int r1, int rt, int x) {
  58. if (max(l, l1) > min(r, r1)) {
  59. return inf;
  60. }
  61. if (l >= l1 && r <= r1) {
  62. if (tree[rt] > x) {
  63. return inf;
  64. }
  65. if (l == r) {
  66. return l;
  67. }
  68. int t = (l + r) / 2;
  69. if (tree[rt * 2 + 1] <= x) {
  70. return getl(l, t, l1, r1, rt * 2 + 1, x);
  71. }
  72. return getl(t + 1, r, l1, r1, rt * 2 + 2, x);
  73. }
  74. int t = (l + r) / 2;
  75. int p = getl(l, t, l1, r1, rt * 2 + 1, x);
  76. if (p != inf) return p;
  77. return getl(t + 1, r, l1, r1, rt * 2 + 2, x);
  78. }
  79.  
  80. int getr(int l, int r, int l1, int r1, int rt, int x) {
  81. if (max(l, l1) > min(r, r1)) {
  82. return inf;
  83. }
  84. if (l >= l1 && r <= r1) {
  85. if (tree[rt] > x) {
  86. return inf;
  87. }
  88. if (l == r) {
  89. return l;
  90. }
  91. int t = (l + r) / 2;
  92. if (tree[rt * 2 + 2] <= x) {
  93. return getr(t + 1, r, l1, r1, rt * 2 + 2, x);
  94. }
  95. return getr(l, t, l1, r1, rt * 2 + 1, x);
  96. }
  97. int t = (l + r) / 2;
  98. int p = getr(t + 1, r, l1, r1, rt * 2 + 2, x);
  99. if (p != inf) return p;
  100. return getr(l, t, l1, r1, rt * 2 + 1, x);
  101. }
  102.  
  103. void upd(int l, int r, int l1, int r1, int rt, int x) {
  104. if (l >= l1 && r <= r1) {
  105. tree[rt] = x;
  106. return;
  107. }
  108. if (max(l, l1) > min(r, r1)) {
  109. return;
  110. }
  111. int t = (l + r) / 2;
  112. upd(l, t, l1, r1, rt * 2 + 1, x);
  113. upd(t + 1, r, l1, r1, rt * 2 + 2, x);
  114. tree[rt] = min(tree[rt * 2 + 1], tree[rt * 2 + 2]);
  115. }
  116.  
  117. struct Req {
  118. int val, id, l, r;
  119. Req(int a, int b, int c, int d) : val(a), id(b), l(c), r(d) {}
  120. Req() : val(0), id(0), l(0), r(0) {}
  121. };
  122.  
  123. vector<Req> have;
  124.  
  125. vector<pii> left[maxn];
  126. vector<pii> right[maxn];
  127. vector<int> have_all[maxn];
  128.  
  129. struct Scan {
  130. int ty, x, val;
  131. Scan(int a, int b, int c) : ty(a), x(b), val(c) {}
  132. Scan() : ty(0), x(0), val(0) {}
  133. };
  134.  
  135. vector<Scan> scan[maxn];
  136.  
  137. bool cmp(Scan p1, Scan p2) {
  138. return (p1.x < p2.x) || (p1.x == p2.x && p1.ty < p2.ty);
  139. }
  140.  
  141. fenwik L, R;
  142.  
  143. void solve() {
  144. cin >> n;
  145. for (int i = 0; i < n; ++i) {
  146. cin >> cnt[i];
  147. }
  148. build(2 * n);
  149. for (int i = 0; i < n; ++i) {
  150. upd(0, len - 1, i, i, 0, cnt[i]);
  151. }
  152. for (int i = n; i < 2 * n; ++i) {
  153. upd(0, len - 1, i, i, 0, inf);
  154. }
  155. vector<Req> req;
  156. vector<int> kek;
  157. for (int i = 0; i < n; ++i) {
  158. vector<int> idx = {i};
  159. vector<int> val = {cnt[i]};
  160. while (true) {
  161. int p = getl(0, len - 1, idx.back() + 1, len - 1, 0, val.back());
  162. if (p != inf) {
  163. val.pb(val.back() % cnt[p]);
  164. idx.pb(p);
  165. } else {
  166. break;
  167. }
  168. }
  169. idx.pb(n);
  170. for (int j = 0; j < (int)idx.size() - 1; ++j) {
  171. req.eb(val[j], i, idx[j], idx[j + 1] - 1);
  172. cout << val[j] << " " << i << " " << idx[j] << " " << idx[j + 1] - 1 << "\n";
  173. kek.pb(val[j]);
  174. }
  175. }
  176. for (auto v : req) {
  177. if (v.l) {
  178. scan[v.val].eb(-1, v.l - 1, v.id);
  179. }
  180. scan[v.val].eb(1, v.r, v.id);
  181. }
  182. for (int i = 0; i < n; ++i) {
  183. vector<int> idx = {i};
  184. vector<int> val = {cnt[i]};
  185. while (idx[0]) {
  186. int p = getr(0, len - 1, 0, idx.back() - 1, 0, val.back());
  187. if (p != inf) {
  188. val.pb(val.back() % cnt[p]);
  189. idx.pb(p);
  190. } else {
  191. break;
  192. }
  193. }
  194. idx.pb(-1);
  195. for (int j = 0; j < (int)idx.size() - 1; ++j) {
  196. have.eb(val[j], i, idx[j + 1] + 1, idx[j]);
  197. kek.pb(val[j]);
  198. }
  199. }
  200. sort(all(kek));
  201. kek.erase(unique(all(kek)), kek.end());
  202. for (auto v : have) {
  203. int idx = lower_bound(all(kek), v.val) - kek.begin();
  204. scan[v.val].eb(-2, v.l, v.id);
  205.  
  206. scan[v.val].eb(-3, v.r, v.id);
  207.  
  208. have_all[idx].eb(v.id);
  209. }
  210. for (int i = 0; i < maxn; ++i) {
  211. sort(all(scan[i]), cmp);
  212. }
  213. for (int i = 0; i < maxn; ++i) {
  214. sort(all(have_all[i]));
  215. }
  216. int ans = 0;
  217. for (int i = 0; i < maxn; ++i) {
  218. L.clear();
  219. R.clear();
  220. for (auto v : scan[i]) {
  221. if (v.ty == -3) {
  222. R.upd(v.x, 1);
  223. } else if (v.ty == -2) {
  224. L.upd(v.x, 1);
  225. } else {
  226. ans += v.ty * L.sum(v.x + 1, maxn - 1);
  227. ans += v.ty * R.sum(0, v.x - 1);
  228. }
  229. }
  230. }
  231. cout << ans;
  232. }
  233.  
  234.  
  235. signed main() {
  236. #ifdef HOME
  237. freopen("input.txt", "r", stdin);
  238. #else
  239. ios_base::sync_with_stdio(0); cin.tie(0);
  240. #endif
  241. solve();
  242. }
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