project 1

import random
import time
P_win = 0
C_win = 0
print('''welcome to the battle arena
In this game you will be asked to choose 10 warriors from a selection of 3 classes
you can choose however many of each class you want

The rules are relatively simple
footmen beats archer
horsemen beats footmen
archer beats horsemen
its essentially a rock paper scissors triangle with a twist

The game is decided with two battles.
the first battle eliminates numbers based on this rock paper scissors triangle.
The second battle focuses on total remaining forces and the player with the most left wins.
if there is a tie in forces for the second battle it comes down to a luck draw. as battles will always have a winner.
have fun''')
time.sleep(5)
while True:
    P_footmen = 0
    P_horsemen = 0
    P_archers = 0
    C_footmen = 0
    C_horsemen = 0
    C_archers = 0
    print("choose your warriors")
    time.sleep(2)
    while True:
        p = 10
        P_footmen = int(input("Number of footmen? "))
        p -= P_footmen
        print("you have", p, "men left to pick")
        if p == 0:
            break
        time.sleep(1)
        P_horsemen = int(input("Number of horsemen? "))
        p -= P_horsemen
        print("you have", p, "men left to pick")
        if p == 0:
            break
        time.sleep(1)
        P_archers = int(input("number of archers? "))
        p -= P_archers
        if p < 0:
            print("you picked too many warriors. 10 maximum")
        elif p == 0:
            break
        elif p > 0:
            ("you didn't choose enough warriors")
        time.sleep(1)
    print("you choose", P_footmen , "footmen")
    time.sleep(1)
    print(P_horsemen, "horsemen")
    time.sleep(1)
    print("and", P_archers , "archers")
    while True:
        c = 10
        v = random.randint(1,3)
        #in order to make this part of the code much less predictable I added a choose order variable
        #this allows multiple choose orders so the first two choosen aren't the most likely to get more choosen
        #this makes the random element more uniformly random.
        #as well I origionally planned on doing all 9 possible orentations of choose orders but that would have been dreadfully tedious and boring
        if v == 1:
            C_footmen = random.randint(0,c)
            c -= C_footmen
            if c == 0:
                break
            C_horsemen = random.randint(0,c)
            c -= C_horsemen
            if c == 0:
                break
            C_archers = c #the last part of every pick order will always  be c. because it is the last to be picked. and must fill the last requirements
            c -= C_archers
            if c == 0:
                break
        elif v == 2:
            C_archers = random.randint(0,c)
            c -= C_archers
            if c == 0:
                break
            C_footmen = random.randint(0,c)
            c -= C_footmen
            if c == 0:
                break
            C_horsemen = c
            c -= C_horsemen
            if c == 0:
                break
        elif v == 3:
            C_horsemen = random.randint(0,c)
            c -= C_horsemen
            if c == 0:
                break
            C_archers = random.randint(0,c)
            c -= C_archers
            if c == 0:
                break
            C_footmen = c
            c -= C_footmen
            if c == 0:
                break
    time.sleep(1)
    print("computer is choosing.....")
    time.sleep(1)
    print("soldiers selected, let the battle begin!")
    print("   ")
    time.sleep(1)
    print("player sends out", P_footmen, "footmen.", P_horsemen, "horsemen, and", P_archers, "archers")
    time.sleep(1)
    print("against the computer's forces of", C_footmen, "Footmen,", C_horsemen, "horsemen, and", C_archers, "archers")
    #These variables stand for hte remaining of each unit on each team
    PR_footmen = P_footmen - C_horsemen
    PR_horsemen = P_horsemen - C_archers
    PR_archers = P_archers - C_footmen
    CR_footmen = C_footmen - P_horsemen
    CR_horsemen = C_horsemen - P_archers
    CR_archers = C_archers - P_footmen
    #I don't wish for hte game to display negitive numbers so this setup is to solve that
    if PR_footmen < 0:
        PR_footmen = 0
    if PR_horsemen < 0:
        PR_horsemen = 0
    if PR_archers < 0:
        PR_archers =0
    if CR_footmen < 0:
        CR_footmen = 0
    if CR_horsemen < 0:
        CR_horsemen = 0
    if CR_archers < 0:
        CR_archers =0
    time.sleep(3)
    print("battle results are...!")
    print("   ")
    time.sleep(3)
    print("the player with", PR_footmen, "footmen", PR_horsemen, "horsemen, and", PR_archers, " archers remaining")
    time.sleep(3)
    print("and the computer with", CR_footmen, "footmen", CR_horsemen, "horsemen, and", CR_archers, "archers remaining")
    print("   ")
    time.sleep(3)
    while True:
        if PR_footmen == 0 and PR_horsemen == 0 and PR_archers == 0:
            print("The player has lost before the second battle. Computer wins!")
            P_win += 1
            break
        elif CR_footmen == 0 and CR_horsemen == 0 and CR_archers == 0:
            print("the computer has lost before the second battle. Player wins!")
            C_win += 1
            break

        print("the second battle begins!!!")
        print("   ")
        time.sleep(3)
        print("the battle results are...!!")
        time.sleep(3)
        P_total = PR_footmen + PR_horsemen + PR_archers
        C_total = CR_footmen + CR_horsemen + CR_archers
        if P_total > C_total:
            print("player wins with a total force count of", P_total, "versus the computer's", C_total)
            P_win += 1
            break
        elif C_total > P_total:
            print("the computer wins with a total force count of", C_total, "versus the player's", P_total)
            C_win += 1
            break
        elif C_total == P_total:
            print("the forces left over are equal on each side. the battle comes down to a draw of luck!")
            time.sleep(3)
            #I am not allowing a tie as this is a battle, and it is very unlikeley that a tie would occur in a battle.
            #so it comes down to a bit of extra luck if end forces are infact equal
            L = random.randint(1,2)
            if L == 1:
                print("By a stroke of luck the player is victorious!")
                P_win += 1
            elif L == 2:
                print("By a stroke of luck the computer is victorious!")
                C_win += 1
    time.sleep(2)
    end = input("would you like to play again? y/n")
    if end == "n":
        break
    elif end == "y":
        print("player has currently won", P_win, "rounds, and computer", C_win, "rounds")
    else:
        while True:
            end = input("incorrect input. type y or n ")
            if end == "y" or end == "n":
                break
r = P_win + C_win
print("you've ended the game after", r, "rounds")
time.sleep(2)
print("player won", P_win, "rounds, and the computer has won", C_win, "rounds")
time.sleep(2)
if P_win > C_win:
    print("Player is the overal winner!")
elif C_win > P_win:
    print("computer is the overal winner!")
elif C_win == P_win:
    print("the overal game is a tie!")
print("game over")