int N = 456778889;
double expo = Math.log10(N);
int expNum = (int)Math.floor(expo)+1;  //gets the total digits in the Integer N

StringBuilder sb = new StringBuilder("1");
    sb.setLength(expNum);
    String f = sb.toString().replaceAll("[^0-9]","0"); // It makes the 1 followed by X amount of zero that i require to get my MSB
    int mostSigNum = N/(Integer.valueOf(f));
    System.out.println(mostSigNum);

int maxi = (int)(N/Math.pow(10, Math.floor(Math.log10(N))));

int maxi = Character.digit(String.valueOf(N).charAt(0), 10);

int N = 456778889;
double expo = Math.log10(N);
int expNum = (int)Math.floor(expo);

String c = IntStream.range(0,expNum).mapToObj(e->"0").collect(Collectors.joining(""));
    String t = "1".concat(c);
    int maxi = N/Integer.parseInt(t);
    System.out.println(maxi);

public int maxi(int n) {
    return String.valueOf(n)
            .chars()
            .map(i -> i - '0')
            .max()
            .orElse(0);
}

@Test
public void testMaxi() {
    assertEquals(1, maxi(1000));
    assertEquals(7, maxi(7654));
    assertEquals(9, maxi(456778889));
}

int number = 456778889;
int result = IntStream.iterate(number, i -> i / 10) // divide by 10
                      .filter(i -> i < 10)          // filter out if multiple digits
                      .findFirst().getAsInt();      // get the first value

int number = 456778889;
int result;
for (result = number; result >= 10; result /= 10);