#cryptoChallenge - solution

#cryptoChallenge

import random

text = "2×2=5"

def enc(text):
    limiter = chr(2**(2*2*2+2)+2**(2*2+1)-2)
    key = [ord(random.choice(text)) for x in range(2)]
    res = [str(bin(ord(x)*key[0]-key[1])) for x in text[::-1]]
    return '{0}{1}{2}'.format(str(bin(key[0]**2))+limiter, limiter.join(res), limiter + str(bin(key[1]**2))).replace('0b', '').replace(chr(2**(2*2+1)+2**(2+2)+1), chr(2**(2*2+2)+2**(2+2)-1))

def dec(text):
    limiter = chr(2**(2*2*2+2)+2**(2*2+1)-2)
    data = [int('0b'+x, 2) for x in text.replace(chr(2**(2*2+2)+2**(2+2)-1), chr(2**(2*2+1)+2**(2+2)+1)).split(limiter)]
    key = [int(data[0]**(1/2)), int(data[-1]**(1/2))]
    return ''.join([chr(int((x+key[1])/key[0])) for x in data[1:-1][::-1]])

encrypted = enc(text)
print(encrypted)
decrypted = dec(encrypted)
print(decrypted)