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- Aufgabe 8.3
- a)
- A =
- 2 1
- 2 -4
- m
- ||A||1 = max Σ |a(ij)| = max {2 + 2, 1 + |-4|} = max {2, 5} = 5
- j=1,..,n i=1
- -----------------------------------------------------------------------------
- ||A||2 = root(λ(max)(A^T * A))
- A^T * A =
- 2 2 * 2 1 = 2*2+2*2 2*1+2*(-4) = 8 -6
- 1 -4 2 -4 1*2+(-4)*2 1*1+(-4)*(-4) -6 17
- det(A^T * A) = (λ - 8)*(λ - 17) - (-6)² = λ² - 25λ + 100
- λ1/2 = (25 +- root(625 - 400)) / 2
- = (25 +- 15) / 2 = {20, 5}
- ||A||2 = root(20)
- -----------------------------------------------------------------------------
- n
- ||A||∞ = max Σ |a(ij)| = max {2 + 1, 2 + |-4|} = max {3, 6} = 6
- i=1,..,m j=1
- b)
- cond(A)p = ||A||p * ||A^(-1)||p
- A^(-1) =
- 2 1
- 2 -4
- cond(A)∞ = max {3, 6} * max {4, 5} = 6*5 = 30
- Aufgabe 8.4
- A =
- 2 1 1
- 4 3 4
- -6 -5 -6
- b =
- -1
- 2
- -2
- -------------------------------
- L1 =
- 1 0 0
- -2 1 0
- 3 0 1
- -------------------------------
- L1 * A =
- 1 0 0 * 2 1 1
- -2 1 0 4 3 4
- 3 0 1 -6 -5 -6
- =
- 2 1 1
- 0 1 2
- 0 -2 -3
- -------------------------------
- L2 =
- 1 0 0
- 0 1 0
- 0 2 1
- -------------------------------
- L2 * L1 * A =
- 1 0 0 * 2 1 1
- 0 1 0 0 1 2
- 0 2 1 0 -2 -3
- =
- 2 1 1
- 0 1 2
- 0 0 1
- L2*L1*A = R
- <=> L1*A = L2^(-1)*A
- <=> A = L1^(-1)*L2^(-1)*R
- L1^(-1)*L2^(-1) = L
- -------------------------------
- L1^(-1) =
- 1 0 0
- 2 1 0
- -3 0 1
- -------------------------------
- L2^(-1) =
- 1 0 0
- 0 1 0
- 0 -2 1
- -------------------------------
- L1^(-1)*L2^(-1) =
- 1 0 0
- 2 1 0
- -3 -2 1
- = L
- -------------------------------
- L*R =
- 1 0 0
- 2 1 0
- -3 -2 1
- *
- 2 1 1
- 0 1 2
- 0 0 1
- =
- 2 1 1
- 4 3 4
- -6 -5 -6
- = A
- Ax = b <=> LRx = b
- sei Rx = y
- 1) Ly = b
- y1 + 0 + 0 = -1
- 2y1 + y2 + 0 = 2
- -3y1 + -2y2 + y3 = -2
- y1 = -1
- y2 = 4
- y3 = 3
- 2) Rx = y
- 2x1 + x2 + x3 = -1
- 0 + x2 + 2x3 = 4
- 0 + 0 + x3 = 3
- x1 = -1
- x2 = -2
- x3 = 3
- (-1)
- x = (-2)
- ( 3)
- einsetzen in A
- 2x1 + x2 + x3 = (-2) + (-2) + 3 = -1
- 4x1 + 3x2 + 4x3 = (-4) + 3*(-2) + 4*3 = 2
- -6x1 + -5x2 + -6x3 = 6 + 10 + (-18) = -2
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