22

def f(n):
    if n < 2:
        return n
    if n % 2 == 0:
        return f(n//2) + 1
    else:
        return f(3*n + 1) + 1


cnt = 0
for i in range(1, 101):
    if f(i) > 100:
        cnt += 1
print(cnt)