Zbir na cifri

//you could do this with only math and no strings, but why should you when this is simpler?

#include <iostream>
#include <string>

int main() {
    std::string N;
    std::cin >> N;

    int brCif = N.length();

    int suma = 0;

    for (int i = 0; i < brCif; i++) {
        char x = N.at(i);
        int ix = x - '0'; //char --> int
        suma += ix;
    }

    std::cout << suma << std::endl;

    return 0;
}