Sichanov

harvest

May 4th, 2021
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Python 0.82 KB | None | 0 0
  1. import math
  2.  
  3. X = int(input())  # X кв.м е лозето – цяло число в интервала  [10 … 5000]
  4. Y = float(input())  # Y грозде за един кв.м – реално число в интервала [0.00 … 10.00]
  5. Z = int(input())  # Z нужни литри вино – цяло число в интервала [10 … 600]
  6. workers = int(input())  # брой работници – цяло число в интервала [1 … 20]
  7. manifactured_grapes = X * Y
  8. wine = 0.4 * manifactured_grapes / 2.5
  9.  
  10. if wine < Z:
  11.     print(f"It will be a tough winter! More {math.floor(Z - wine)} liters wine needed.")
  12. else:
  13.     print(f"Good harvest this year! Total wine: {math.floor(wine)} liters.")
  14.     print(f"{math.ceil(wine - Z)} liters left -> {math.ceil((wine - Z) / workers)} liters per person.")
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