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Dec 15th, 2017
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  1. SELECT c.firstname, c.lastname, c.email FROM ps_customer c INNER JOIN ps_newsbuild_customer nc WHERE c.newsletter = 1 AND c.id_customer = nc.id_customer AND nc.news = 0
  2.  
  3. SELECT value WHERE X=X and Z=Z and T=T
  4.  
  5. SELECT c.firstname, c.lastname, c.email FROM ps_customer c INNER JOIN ps_newsbuild_customer nc WHERE c.newsletter = 1 AND nc.news = 0
  6.  
  7. Array (
  8. [0] => Array ( [firstname] => John [lastname] => DOE [email] => zz@gmail.com )
  9. [1] => Array ( [firstname] => jaimy [lastname] => DOE [email] => tt@skynet.be )
  10. [2] => Array ( [firstname] => John [lastname] => DOE [email] => zz@gmail.com )
  11. [3] => Array ( [firstname] => jaimy [lastname] => DOE[email] => tt@skynet.be ) )
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