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Apr 25th, 2019
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  1. void LeapYear_Nearly(char* TIME)
  2. {
  3. int dem = 0, A[10], B[10];
  4. int year = Year(TIME);
  5. int yearT = year;
  6. while (yearT > 1) {
  7. yearT--;
  8. if (LeapYear(yearT) == 1) {
  9. /*cout << yearT;*/
  10. for (int i = 0; i < 2; i++)
  11. {
  12. A[i] = yearT;
  13. }
  14. dem += 1;
  15. if (dem == 2) break;
  16. }
  17. }
  18. yearT = year;
  19. dem = 0;
  20. while (1) {
  21. yearT++;
  22. if (LeapYear(yearT) == 1) {
  23. /*cout << yearT;*/
  24. for (int i = 0; i < 2; i++)
  25. {
  26. B[i] = yearT;
  27. }
  28. dem += 1;
  29. if (dem == 2) break;
  30. }
  31. }
  32. for (int i = 0; i < 2; i++)
  33. {
  34. for (int j = 0; j < 2; j++)
  35. {
  36. if (year - A[i] < B[j] - year) // int year=Year(TIME)
  37. cout << A[i];
  38. else
  39. cout << B[j];
  40. }
  41. }
  42. }
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