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Jun 26th, 2019
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  1. SELECT
  2. [Master_ID]
  3. ,COUNT(DISTINCT [parent_file_id]) AS Number_of_parent_files
  4. ,COUNT([Child_ID]) AS Number_of_child_files
  5. FROM [EXAMPLE_TABLE]
  6. GROUP BY [Master_ID]
  7. ORDER BY 1
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