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Feb 19th, 2020
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  1. //@and
  2. #include <iostream>
  3.  
  4. using namespace std;
  5. int a[101][101],i,j,m,n;
  6. int div(int a[101][101], int l1, int c1, int l2, int c2)
  7. {
  8. if(l1==l2)
  9. {
  10. int sol=0;
  11. for(int j=c1;j<=c2;j++)
  12. {
  13. if(a[l1][j]%2==0) sol+=a[l1][j];
  14. }
  15. return sol;
  16. }
  17. else
  18. {
  19. int m1=(c1+c2)/2;
  20. int m2=(l1+l2)/2;
  21. return div(a,l1,c1,m2,m1)+div(a,l1,m1+1,m2,c2)+div(a,m2+1,c1,l2,m1)+div(a,m2+1,m1+1,l2,c2);
  22. }
  23. }
  24. int main()
  25. {
  26. cin>>m>>n;
  27. for(i=1;i<=m;i++) for(j=1;j<=n;j++) cin>>a[i][j];
  28. cout<<div(a,1,1,m,n);
  29. }
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