string reverse (string temp , int length )
{
    if(length==1)
    { return temp; }
        else
    {


    int t = (temp.length ()+1) / 2;
    return  (reverse( temp.substr(t, temp.length() -1 ), t) + reverse (  temp.substr(0 ,t ) ,t  )  );



       }

}

int main( ) {
    string s;
    cin>>s;
    string rev = reverse (s , s.length() );
    cout <<"n"<<rev;
    cin>>s;

    return 0;
}